b^2-8=2b

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Solution for b^2-8=2b equation:


Simplifying
b2 + -8 = 2b

Reorder the terms:
-8 + b2 = 2b

Solving
-8 + b2 = 2b

Solving for variable 'b'.

Reorder the terms:
-8 + -2b + b2 = 2b + -2b

Combine like terms: 2b + -2b = 0
-8 + -2b + b2 = 0

Factor a trinomial.
(-2 + -1b)(4 + -1b) = 0

Subproblem 1

Set the factor '(-2 + -1b)' equal to zero and attempt to solve: Simplifying -2 + -1b = 0 Solving -2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1b = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1b = 0 + 2 -1b = 0 + 2 Combine like terms: 0 + 2 = 2 -1b = 2 Divide each side by '-1'. b = -2 Simplifying b = -2

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {-2, 4}

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